I said, using the quotient rule, f'(x)[1(lnx) - x(1/x)]/(lnx)^2 = lnx - 1 so f'(e) = (lne - 1) / (lne)^2 = 1-1/1 = 0/1 = 0

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Originally Posted by satx I said, using the quotient rule, f'(x)[1(lnx) - x(1/x)]/(lnx)^2 = lnx - 1 <... ? so f'(e) = (lne - 1) / (lne)^2 = 1-1/1 = 0/1 = 0 so which means you're right

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