I said

f'(x) = m = 0 = 2xe^2x ---> x = 0/(2xe^2x) = 0

Is this right?

- Apr 4th 2010, 08:30 AMsatxFor what x value does the tangent of the graph of f(x) = xe^2x have a slope = 0?
I said

f'(x) = m = 0 = 2xe^2x ---> x = 0/(2xe^2x) = 0

Is this right? - Apr 4th 2010, 08:37 AMe^(i*pi)
- Apr 4th 2010, 08:41 AMsatx
Wouldn't that equal 2?

- Apr 4th 2010, 08:50 AMRaoh
- Apr 4th 2010, 08:53 AMRaoh
to solve

:) - Apr 4th 2010, 08:54 AMsatx
Ok then that would equal one then, if x = 0, no? (e^2(0))(0) + e^2(0)) = 0 + 1 = 1???

- Apr 4th 2010, 08:55 AMsatx
- Apr 4th 2010, 08:56 AMRaoh
- Apr 4th 2010, 08:58 AMsatx
- Apr 4th 2010, 09:05 AMRaoh
- Apr 4th 2010, 09:15 AMRaoh