Q: Use implicit differentiation to find an equation of the line tangent to the curve yx^2 + xy^2 = 6 at the point (1, 2).

Here's my answer... it is right?

2x(d/dx) + 2y(d/dx) = 6(d/dx) = 0 --> (d/dx)(2x + 2y) = 0 --> dy/dx = 0/(2x + 2y) = 0 = m

y = mx + b = 0x + b = b = 2 -->y =2