So here's my problem: Find a function y of x such that: $\displaystyle \displaystyle3yy\prime=x$ and $\displaystyle y(3)=5$ any hints on how to start out?
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Originally Posted by ascendancy523 So here's my problem: Find a function y of x such that: $\displaystyle \displaystyle3yy\prime=x$ and $\displaystyle y(3)=5$ any hints on how to start out? $\displaystyle 3y \cdot \frac{dy}{dx} = x$ separate variables ... $\displaystyle y \, dy = \frac{x}{3} \, dx$ now integrate.
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