um.. if you sub in sqrt(x) to the u^2 wouldn't that make ity=u^2+3u, u=square root of x
y = x + 3sqrt(x)?
Using Leibniz notation, apply the chain rule to determine dy/dx at x=4.
y=u^2+3u, u=square root of x
So I rewrite square root of x as x^1/2
dy/du = 1/2x^-1/2
du/dx = 2u+3
dy/dx = (dy/du)(du/dx)
= 1/2x^-1/2 (2u+3)
= 1/2x^-1/2 [2(x^1/2)+3] *subbed in u
= 2(x^1/2)+3 / 1/2x^1/2
= 2(x^1/2)+3 / square root of 1/2x
The answer is 7/4, however my answer when I sub in x=4 is 7/1.414213562
What did I do wrong?