Integrate

sqrt (x^2 -4) using the substitution x = 2sec@

I had:

x = 2sec@

dx = 2sec@tan@

sqrt (4sec^2 @ -4) x 2sec@tan@ d@

= 4tan^2 @ sec@

and now I'm stuck.

Thanks

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- Apr 2nd 2010, 03:47 AMdifferentiateintegrate using substitution x = 2sec@
Integrate

sqrt (x^2 -4) using the substitution x = 2sec@

I had:

x = 2sec@

dx = 2sec@tan@

sqrt (4sec^2 @ -4) x 2sec@tan@ d@

= 4tan^2 @ sec@

and now I'm stuck.

Thanks - Apr 2nd 2010, 03:51 AMSudharaka
- Apr 2nd 2010, 03:51 AMTed