Hello please help me with the following question if you can…
X = 4 sin (2y + 6), find dy/dx in terms of x
Please help me, I am stuck in a rut with this … I have a brain drain and the urge to burn this question.
If so, we can solve the original problem for y, then differentiate in terms of x:
x = 4sin(2y + 6)
y = 1/2*arcsin(x/4) - 3
dy/dx[y] = dy/dx[1/2*arcsin(x/4) - 3]
dy/dx = 1/(8sqrt(1 - (x/4)^2))