limit as x goes to 0 of - Wolfram|Alpha[%28Log[x]%29%2F%28Log[Cos[x]]%29]
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y = lim [X->0] (ln x)/ ln ( cos x)
can't use L'Hopital's rule since the indeterminant form is infinity/0. you can use it only when it's 0/0 or infinity/infinity.
the final answer is positive infinity, but i don't know how to get there. been at it for days
Thanks
limit as x goes to 0 of - Wolfram|Alpha[%28Log[x]%29%2F%28Log[Cos[x]]%29]
Click show steps.
any time the denominator goes to zero or the numerator goes to infinity the expression goes to infinity
Similarly any time the numerator goes to zero or the denominator goes to infinity the expression goes to zero
The only exception is when both numerator and denominator approach infinity or zero