Hi. Evaluate. $\displaystyle \Sigma^{\infty}_{n = 1}\frac{4^{2n}}{n! n^2}$
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What makes you think it has a cloesd form? I foresee some $\displaystyle Ei(x)$s
Try ratio.. Or one of those tests to see if your series converges.
See here : http://www.mathhelpforum.com/math-he...lp-series.html I sometimes feel so useful
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