Do you know Descartes rule of sign?
we first used newtons method to find the approximate value of 200^(1/7) and got it equal to the awnser in the caclulator which is = 2.131663117
i need some help in the right direction on how to solve the question after solving the above equation using newtons method!
the fundamental theorem of algebra guarantees that the equation x^7-200 = 0 must have 7 solutions. You have just found one of these. Are there any more real solutions? Use your tools of calculus to sustain your awnser.
But the question requires that you use HallsofIvy's method not the rule of signs.