I'm completely stumped as far as this problem goes. I've got to find the volume of this solid and I can't figure out the area of the cross section. It starts out like this:
After talking to my instructor, I realized that the cross section I can see on the graph is half of the square cross section. Basically I figure that I find the volume of what I can see from the graph and double it.The solid lies between planes perpendicular to the x-axis at x=0 and x=4. The cross sections perpendicular to the axis on the x interval [0,4] are squares whose diagonals run from y=-√x to y=√x.
So I find that the base of the triangle is 2√x. Unfortunately I can't seem to go any farther, because I have neither a height nor any of the two equal sides. I'm wondering if there's a way I haven't thought of to find the area of this triangle.
I realize, by the way, that this is more of a geometry problem than a calculus one, but I posted it here anyway in case there was something in the initial concept I missed.