Kirchoff's first law gives the relationship E(t) = L * (di/dt) + R*i where L is the inductance, R is the resistance and i is the current.

$\displaystyle

\begin{tabular}{|c|c|c|c|c|c|}

\hline

$\emph{t}$ & 1.00 & 1.01 & 1.02 & 1.03 & 1.04\\

\hline

$\emph{i}$ & 3.10 & 3.12 & 3.14 & 3.18 & 3.24\\

\hline

\end{tabular}

$

Suppose t is measured in seconds, i is in amperes, the inductance L is a constant 0.98 henries and R is 0.142 ohms. Approximate the voltage E(t) when t = 1.00, 1.01, 1.02, 1.03, 1.04.

How do I solve di/dt? That's the derivative of i with respect to t I think but there's no formula for i. So I'm not even sure what E(1.00) is supposed to be.