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Thread: Area of cardioid

  1. #1
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    Area of cardioid

    How do you find the area inside of the cardioid r=1-cos(theta) for 0<=theta<=2*pi

    Is it just the integral between 0 and 2pi of 1/2* (1-cos(theta))^2, which you can simply foil out and do easily? Or do you need to use the graph for something?
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  2. #2
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    Quote Originally Posted by twittytwitter View Post
    How do you find the area inside of the cardioid r=1-cos(theta) for 0<=theta<=2*pi

    Is it just the integral between 0 and 2pi of 1/2* (1-cos(theta))^2, which you can simply foil out and do easily? Or do you need to use the graph for something?
    just what you said.
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