http://www.flickr.com/photos/4882931...18204/sizes/l/ Its number 5. The value was changed to plus/minus 0.05 How should i go about solving this problem?
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bump... anyone? i need to have this figured out by tomorrow >.<
Since no one here has any idea what you mean by "L9(x)", I don't see how anyone can help you.
It means the linearization (tangent line) at x=9
The derivative of is . At x= 9 that is while [tex]\sqrt{9}= 3[/math so the tangent line at x= 9 is . In order that that be within of the actual value, we must have or . Solve and .
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