Another Limit Calculation problem

**azarue** · March 30th 2010, 08:01 AM

Hi Forum Members.

I need your help with another limit problem. Thanks in advance.

**tonio** · March 30th 2010, 08:18 AM

Originally Posted by azarue

Hi Forum Members.

I need your help with another limit problem. Thanks in advance.

You should know that in this kind of limits what matters is the degree of the numerator and denominator polynomials and their corresponding leading coefficients, so you can write:

$\frac{(4x-1)^{30}(2x+4)^{90}}{(2x-1)^{120}}=\frac{(4^{30}x^{30}+P(x))(2^{90}x^{90}+Q (x))}{2^{120}x^{120}+R(x)}$ , where $P(x),\,Q(x),\,R(x)$ are polynomials of degree less than or equal 29,89,129, corresp.

Well, since $4^{30}2^{90}=2^{150}$ , the limit is...

Tonio

**azarue** · April 1st 2010, 04:25 AM

I had to read more about that subject, but mainly I got this. Thank you.

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Thank you for your solution.

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