# Math Help - Another Limit Calculation problem

1. ## Another Limit Calculation problem

Hi Forum Members.

2. Originally Posted by azarue
Hi Forum Members.

You should know that in this kind of limits what matters is the degree of the numerator and denominator polynomials and their corresponding leading coefficients, so you can write:

$\frac{(4x-1)^{30}(2x+4)^{90}}{(2x-1)^{120}}=\frac{(4^{30}x^{30}+P(x))(2^{90}x^{90}+Q (x))}{2^{120}x^{120}+R(x)}$ , where $P(x),\,Q(x),\,R(x)$ are polynomials of degree less than or equal 29,89,129, corresp.

Well, since $4^{30}2^{90}=2^{150}$ , the limit is...

Tonio