# Another Limit Calculation problem

• March 30th 2010, 08:01 AM
azarue
Another Limit Calculation problem
Hi Forum Members.

• March 30th 2010, 08:18 AM
tonio
Quote:

Originally Posted by azarue
Hi Forum Members.

$\frac{(4x-1)^{30}(2x+4)^{90}}{(2x-1)^{120}}=\frac{(4^{30}x^{30}+P(x))(2^{90}x^{90}+Q (x))}{2^{120}x^{120}+R(x)}$ , where $P(x),\,Q(x),\,R(x)$ are polynomials of degree less than or equal 29,89,129, corresp.
Well, since $4^{30}2^{90}=2^{150}$ , the limit is...