Another Limit Calculation problem

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Hi Forum Members.

I need your help with another limit problem. Thanks in advance.

Quote:

Originally Posted by azarue

Hi Forum Members.

I need your help with another limit problem. Thanks in advance.

You should know that in this kind of limits what matters is the degree of the numerator and denominator polynomials and their corresponding leading coefficients, so you can write:

$\frac{(4x-1)^{30}(2x+4)^{90}}{(2x-1)^{120}}=\frac{(4^{30}x^{30}+P(x))(2^{90}x^{90}+Q (x))}{2^{120}x^{120}+R(x)}$ , where $P(x),\,Q(x),\,R(x)$ are polynomials of degree less than or equal 29,89,129, corresp.

Well, since $4^{30}2^{90}=2^{150}$ , the limit is...

Tonio

Thank you for your solution.

I had to read more about that subject, but mainly I got this. Thank you.