Thread: Calculate M4

Calculate for over . _______

Originally Posted by tbenne3

Calculate for over . _______

What is meant to mean? MIdpoint Rule using 4 rectangles?

Please remember that notation that is obvious to you the person wanting help is not always obvious to us the people you want help from.

Originally Posted by mr fantastic

What is meant to mean? MIdpoint Rule using 4 rectangles?

Please remember that notation that is obvious to you the person wanting help is not always obvious to us the people you want help from.

Sorry about that, it stands for Midpoint Approximation (Mn)

Originally Posted by tbenne3

Sorry about that, it stands for Midpoint Approximation (Mn)

OK, so your textbook and class notes will have a formula and examples. Where are you stuck here?

Originally Posted by mr fantastic

OK, so your textbook and class notes will have a formula and examples. Where are you stuck here?

Ok well in the text they have a similar problem to look at and it has
f(x)=x^2, [0,1]

and their solution is

(1/4)(.125^2+.375^2+.625^2+.875^2)

I cant figure out where they are getting the .125,.375,.625,.875

Originally Posted by tbenne3

Ok well in the text they have a similar problem to look at and it has
f(x)=x^2, [0,1]

and their solution is

(1/4)(.125^2+.375^2+.625^2+.875^2)

I cant figure out where they are getting the .125,.375,.625,.875

In that example, they are dividing the interval [0,1] into 4 equal sub-intervals, like so:

[0,0.25] [0.25,0.5] [0.5,0.75] and [0.75,1]

Next, you need to find the midpoint of each interval, because this is what you will use to plug into f(x) for each sub-interval.

Midpoint of [0,0.25] is 0.125
Midpoint of [0.25,0.5] is 0.375
etc.