Try and learn how to draw them in Mathematica then put it into the form:
So z goes from the x-y plane up to the function , y goes from the two "function" of x, y=-4 and y=4 and then x goes from the range of -4 to 4:
Here is my question
Evaluate the triple integral where is bounded by the parabolic cylinder and the planes and .
I set up dV to be dzdydx and the bounds to be {z,0,16-y^2}, I am confused on what to do for y, and {x,-4,4}. I tried {y,-4,4} because that is where the function crosses the z=0 plane, but when I evaluated it, it ended up to be incorrect. Any help would be greatly appreciated.