I'm doing a differential equation problem, kind of confused on a simple integration of sin(pi*t)... which supposedly equals (1/pi)sin(pi*t) + c The problem was... y/t^2 = INT(cos(pi*t))dt Why is it 1/pi?
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Originally Posted by pakman I'm doing a differential equation problem, kind of confused on a simple integration of sin(pi*t)... which supposedly equals (1/pi)sin(pi*t) + c The problem was... y/t^2 = INT(cos(pi*t))dt Why is it 1/pi? What is integral, INT cos (2x) dx = 1/2 * sin (2x) +C What about, INT cos (3x) dx = 1/3*sin(3x) +C ... In general if k!=0 then, INT cos(kx) dx = 1/k*sin (kx)+C Use the substitution t=kx.
If you can express your phone number as a sum of four squares, wouldn't that imply you knew your own phone number?
Originally Posted by AfterShock If you can express your phone number as a sum of four squares, wouldn't that imply you knew your own phone number? Ah! But not by Lagrange's 4 Square theorem. Or Fermat's Polygonal Number Theorem.
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