I came up with but I worked it in a hurry!
use cylindrical shells to find the volume of the solid generated when the region bounded by xy = 4, x + y = 5 is revolved about the x -axis. i did the work for this problem i was wondering if someone could check my work and let me know if my setup for this problem is right? thanks in advance...IMG.pdf
i cant add the second page, but my answer, the final answer for the problem was volume = (58/6)pi
I'm not sure what your asking, but using the shell method and rotating the solid about the x-axis would require the equation:
And if so, p(y) = y, the distance from the axis of revolution to the representaive rectangle (incremental slice) and h(y) would represent the length of the representative rectangle which would be the difference of the two given functions x = 5 - y minus x = 4/y.