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Thread: Where am i going wrong on this simple integration

  1. March 28th 2010, 04:50 PM #1
    vinson24
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    Where am i going wrong on this simple integration

    \int\ (4-2x)^3
    First i factor out a -2
    -2\int\ (x-2)^3
    then u=x-2
    du=1
    -2\int\ u^3du
    \frac{-1}{2}(x-2)^4+C
    but the book has -2(x-2)^4+C
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  2. March 28th 2010, 04:54 PM #2
    pickslides
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    <br /> (4-2x)^3\neq-2\ (x-2)^3<br />
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  3. March 28th 2010, 05:17 PM #3
    skeeter
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    let u = 4-2x

    du = -2 \, dx
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