Thread: Where am i going wrong on this simple integration

1. Where am i going wrong on this simple integration

$\int\ (4-2x)^3$
First i factor out a -2
$-2\int\ (x-2)^3$
then $u=x-2$
$du=1$
$-2\int\ u^3du$
$\frac{-1}{2}(x-2)^4+C$
but the book has $-2(x-2)^4+C$

2. $
(4-2x)^3\neq-2\ (x-2)^3
$

3. let $u = 4-2x$

$du = -2 \, dx$