$\displaystyle \int\ (4-2x)^3$
First i factor out a -2
$\displaystyle -2\int\ (x-2)^3$
then $\displaystyle u=x-2$
$\displaystyle du=1$
$\displaystyle -2\int\ u^3du$
$\displaystyle \frac{-1}{2}(x-2)^4+C$
but the book has $\displaystyle -2(x-2)^4+C$
$\displaystyle \int\ (4-2x)^3$
First i factor out a -2
$\displaystyle -2\int\ (x-2)^3$
then $\displaystyle u=x-2$
$\displaystyle du=1$
$\displaystyle -2\int\ u^3du$
$\displaystyle \frac{-1}{2}(x-2)^4+C$
but the book has $\displaystyle -2(x-2)^4+C$