y' =(ln x)/xy
y(1)=2
and
y'=y
y(0) = 1
HELP!
$\displaystyle \frac{dy}{dx} = \frac{\ln x}{xy}$
$\displaystyle y~dy = \frac{\ln x}{x}~dx$
$\displaystyle \int y~dy = \int \frac{\ln x}{x}~dx$
$\displaystyle \frac{dy}{dx} = y$
$\displaystyle \frac{dy}{y} = dx$
$\displaystyle \int \frac{dy}{y} = \int ~1 dx$