Find the Maclaurin series of f (x) =(1+x^2)^(2/3).. Hey I just need help with this problem please dont give me general equations for maclaurin seres questions I need to know how to solve this one.. Thanks
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$\displaystyle f(x) = (1+x^2)^(2/3)$
Originally Posted by lilaziz1 $\displaystyle f(x) = (1+x^2)^(2/3)$ Yeah thanks.
$\displaystyle f(x)=(1+x^2)^(2/3)$
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