So here's the problem:

A curve is represented parametrically by x = (t²-1)², y = t³. Find dy/dx in terms of t and show that

$\displaystyle

\frac {d^2 y}{dx^2} =

\frac {-3(t^2 +1)}{16t(t^2- 1)^3}

$

I tried to work it out, and I got

dy/dx = $\displaystyle

\frac{3t^2}{4t^3-4t}

$ (not sure if it's correct). And about the second derivative, it got too complicated.

Thanks for any help.