having trouble with his, do I just work backwards? Let f(x,y) be a function whose graph is a plane. Given that f x (1,2)= -3 and f y (1,2) = 2 and that f(0,0) = 4 find f(x,y)
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If "its graph is a plane" then f(x,y)= Ax+ By + C. Now what are $\displaystyle f_x(x,y)$ and $\displaystyle f_y(x,y)$?
f_x(x,y) = A and f_y(x,y) = B ??
is it f(x,y) = -3x + y + 4 = 0?
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