Originally Posted by
Ife thanks... but i don't even understand that! i wonder if my calculations are correct? Let me give you the entire question:
Find the volume of the solid generated by revolving the region in the 1st quadrant bounded above by the line y=1, below by the curve $\displaystyle y= \sqrt{sin 4x}$, and on the left by the y-axis, about the line y=-1...
So i calculated this to be done by the washer method, with an inner radius of $\displaystyle \sqrt{sin 4x}+1$ and an outer radius of 2. So the volume would be: $\displaystyle (\int{3- 2\sqrt{sin4x} - sin 4x} ) dx$ is this correct? From there i was stuck on the integral of the middle term...