How do I go about factoring this correctly? (the bold) f(x)= 2x^3-x^2-4x+8 F^1(x) = 3x^2-2x-4 (3x ) (x ) ?
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Originally Posted by JumpinJimmy How do I go about factoring this correctly? (the bold) f(x)= 2x^3-x^2-4x+8 F^1(x) = 3x^2-2x-4 (3x ) (x ) ? Dear JumpinJimmy, Do you mean that you have to factorize, ???
yeah sorry about the confusion, do not know the short cuts for subscripts and superscripts.
Originally Posted by JumpinJimmy yeah sorry about the confusion, do not know the short cuts for subscripts and superscripts. Dear JumpinJimmy, Hope this will help you.
Originally Posted by JumpinJimmy How do I go about factoring this correctly? (the bold) f(x)= 2x^3-x^2-4x+8 F^1(x) = 3x^2-2x-4 (3x ) (x ) ? The derivative is actually . So if you are setting it equal to 0 and factorising So or or .
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