I need to integrate 1/(16x^3-4x^2+4x-1)
I first split the denominator into (4x-1)(4x^2+1) and used partial fraction decomposition to get:
the integral of (4/5)/(4x-1)+((-4/5)x-(1/5))/(4x^2+1)
I know how to solve the first segment of the integral, but I don't know how to integrate ((-4/5)x-(1/5))/(4x^2+1)