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Math Help - an integral ∫[x^(1/2)][e^(-x/2)]dx

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    an integral ∫[x^(1/2)][e^(-x/2)]dx

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  2. #2
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    Quote Originally Posted by sainimu78 View Post
    You can solve it by integration by parts.
    According to ILATE rule, first function should be Algebraic and the second function should be Exponential.
    e^-(x/2)*1/(2*x^1/2) - Intg[e^-(x/2)*e^-(x/2)*1/(2*x^1/2)
    To solve second integration I, put x^1/2 = t , then x = t^2
    1/(2*x^1/2)*dx = dt
    dx = 2*x^1/2*dt = 2t*dt
    So
    I = Intg[e^-(t^2)/2*t dt.
    Again find the integration by parts to get the final answer.
    Last edited by sa-ri-ga-ma; March 26th 2010 at 06:44 AM.
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    e^-(x/2)*1/(2*x^1/2) - Intg[e^-(x/2)*e^-(x/2)*1/(2*x^1/2) ~?
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