Thread: an integral ∫[x^(1/2)][e^(-x/2)]dx

Originally Posted by sainimu78

You can solve it by integration by parts.
According to ILATE rule, first function should be Algebraic and the second function should be Exponential.
e^-(x/2)*1/(2*x^1/2) - Intg[e^-(x/2)*e^-(x/2)*1/(2*x^1/2)
To solve second integration I, put x^1/2 = t , then x = t^2
1/(2*x^1/2)*dx = dt
dx = 2*x^1/2*dt = 2t*dt
So
I = Intg[e^-(t^2)/2*t dt.
Again find the integration by parts to get the final answer.

e^-(x/2)*1/(2*x^1/2) - Intg[e^-(x/2)*e^-(x/2)*1/(2*x^1/2) ~?