Does anybody know how to get the surface area under this parametric curve about the x axis? I've been trying for hours..
x= 8(t^2)
y= 64t - (t^3)/3
0 <= t <= 8sqrt(3)
My work:
S = 2pi(integral(((64t - (t^3)/3)sqrt((16t^2 + (64-t^2)^2)dt
from 0 to 8sqrt(3)
S = 2pi(integral(((64t - (t^3)/3)sqrt((128t^2+4096t^4)dt
from 0 to 8sqrt(3)