Find the area between $\displaystyle y = 20-x^2 $ and $\displaystyle y=x^2-12$

I found the integral to be

$\displaystyle \int_{-4}^{4}[(20-x^2)-(x^2-12)]dx $

and after evaluating that i found the area to be 170.66667

Does this seem correct?

Thank you?