Find the area between and
I found the integral to be
and after evaluating that i found the area to be 170.66667
Does this seem correct?
Thank you?
y=x^2-12 is a parabola pointing upwards with vertex at (0,-12) while the other is a parabola pointing downwards with vertex at (0,20). both of them meet at(+-4,4).
Now integrating along the x-axis will lead to complications. better will be to integrate along y-axis.then the integral will be from 20 to -12and the expression will be as in the attachment.
Looking at my original graph again of y=20-x^2 and y=x^2-12 i notice that there is more area above the x axis than below so it doesnt seem right to me that the area is 0. Just from looking at the graph it looks like the area should maybe be a positive number????