Thread: word problem (rectangular)

a rectangular has one vertex(corner) at (0,0) and the diagonally opposite vertex(corner) in the first quadrant on the curve of the function y = 1/(1+x^2). find the dimensions of the rectangle with the largest area.

how do i do this question?

would area be a = (2x)(1/(1+x^2)) ?

Originally Posted by haebinpark

a rectangular has one vertex(corner) at (0,0) and the diagonally opposite vertex(corner) in the first quadrant on the curve of the function y = 1/(1+x^2). find the dimensions of the rectangle with the largest area.

how do i do this question?

first, and most important, make a sketch.

then write the area as a function of x ...



now find and maximize like you were taught.

do i find derivative of a = 1/(1+x^2)?
not derivative of a = (2x)(1/(1+x^2))?

Originally Posted by haebinpark

do i find derivative of a = 1/(1+x^2)?
not derivative of a = (2x)(1/(1+x^2))?

once again with more clarity ...

the area of the rectangle in quad I is