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Math Help - relative extrema.

  1. #1
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    relative extrema.

    im not sure how to do this problem.

    given the following function, state the x-coordinate of any relative extrema and identify as a maximum or minimum. justify your answer.

    f(x)= e^x^2-4x

    so x^2-4x is the exponent for e..

    thank you.
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  2. #2
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    Quote Originally Posted by akilele View Post
    im not sure how to do this problem.

    given the following function, state the x-coordinate of any relative extrema and identify as a maximum or minimum. justify your answer.

    f(x)= e^x^2-4x

    so x^2-4x is the exponent for e..

    thank you.
    Did you do something for it?
    Start by taking the derivative ..
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  3. #3
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    okay.. so the derivative is e(2x-4)... uhhh...and then i need to set the equatioin = to 0? and then what would i do after that?
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  4. #4
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    Quote Originally Posted by FinalFantasy9291 View Post
    okay.. so the derivative is e(2x-4)... uhhh...and then i need to set the equatioin = to 0? and then what would i do after that?
    Your derivative is wrong ..
    If f(x)=e^{g(x)} , then f'(x)=g'(x) \, e^{g(x)} ..
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  5. #5
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    ooh crap..

    2x-4e^x^2-4x is the derivative. should be correct i hope.
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  6. #6
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    Quote Originally Posted by FinalFantasy9291 View Post
    ooh crap..

    2x-4e^x^2-4x is the derivative. should be correct i hope.
    Correct.
    Now, you should know what should you do ..
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  7. #7
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    uhh i think i set it equal to 0 but im really not sure what else to do with this problem.. my calc teacher can't teach >.<
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