Use integration to find the area of the triangle having given the vertices

(0,0), (a,0),(b,c)

So I drew out my graph and I got 2 lines

y=c/b(x) and y=(c/b-a)(x-a)

and I know you have to integrate c/b(x) from 0 to b and add that to the integral of (c/b-a)(x-a) from b to a

Im just really having trouble integrating and getting the answer [which is .5(c)(a)]

Please Help