2x = 4 sec t

x = 2 sec t

How can I proceed? I don't think there's an identity to simplify sec^2 t - 1.

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- Mar 25th 2010, 09:17 AMArchduke01trigonometric substitution

2x = 4 sec t

x = 2 sec t

How can I proceed? I don't think there's an identity to simplify sec^2 t - 1. - Mar 25th 2010, 09:52 AMione
- Mar 25th 2010, 10:04 AMArchduke01
- Mar 25th 2010, 10:18 AMGrandad
- Mar 25th 2010, 10:24 AMArchduke01
I know trig sub isn't necessary, but I've been asked to use it since it's the new topic. Thank you for your time, though.

- Mar 25th 2010, 10:33 AMione
- Mar 25th 2010, 10:43 AMArchduke01
- Mar 25th 2010, 10:47 AMione
- Mar 25th 2010, 11:01 AMArchduke01
So it becomes;

? - Mar 25th 2010, 11:06 AMione
- Mar 25th 2010, 11:20 AMArchduke01
Right so I have;

4 (tan x + x) + C

Now I've got to construct that triangle. Since originally my x = 2 sec t, it becomes sec t = x/2. If we're looking for the cos it becomes cos t = 2/x. So on the triangle, the hypotenuse is x while the two sides are 2 and

But it's wrong apparently... - Mar 25th 2010, 11:39 AMione
I find it helpful to draw a right triangle when I begin using trig substitution

Label one of the acute angles t

Since http://www.mathhelpforum.com/math-he...58b07ee3-1.gif, label the hypotenuse 2x and the adjacent side 4

Then the opposite side will be http://www.mathhelpforum.com/math-he...073fed3f-1.gif

http://www.mathhelpforum.com/math-he...7a4b5484-1.gif

http://www.mathhelpforum.com/math-he...f1093caa-1.gif - Mar 25th 2010, 11:52 AMArchduke01
- Mar 25th 2010, 02:35 PMione
- Mar 25th 2010, 02:43 PMGrandad