The initial question was (if anyone is interested):
Find the area of the surface obtained by rotating the curvefrom to about the -axis.
but I am stuck at the integral mentioned above. Having just checked. I do not get the right answer when I use math software so I guess I did something wrong prior to getting this integral.
Here is the integral I am finding tough to do:
integrate 4*pi*sqrt(x)*sqrt(&# x28;sqrt(x) + 2)/sqrt(x)), from 0 to 2 - Wolfram|Alpha
I am probably not using the right integral since using math software gives me the wrong answer so any help would be greatly appreciated!
Thanks in advance!