Thread: Finding the slope given X^5sin(x) when X=.58?

So I am supposed to find the slope, m I presume.

Anyways, I tried to get the derivative using the quotient rule.

THat is: (f * 'g) - (g * 'f)

So:

X^5*Sin(X)

(x^5)(Cos(X)) = (Sin(X))(5x^4)

But when X=.58 I got a super tiny answer.

I believe the answer was 0.3something something.
Thank you for any ideas/hints!

Originally Posted by EJ123

So I am supposed to find the slope, m I presume.

Anyways, I tried to get the derivative using the quotient rule.

THat is: (f * 'g) - (g * 'f)

So:

X^5*Sin(X)

(x^5)(Cos(X)) = (Sin(X))(5x^4)

But when X=.58 I got a super tiny answer.

I believe the answer was 0.3something something.
Thank you for any ideas/hints!

Use the product rule