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Math Help - Finding the slope given X^5sin(x) when X=.58?

  1. #1
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    Question Finding the slope given X^5sin(x) when X=.58?

    So I am supposed to find the slope, m I presume.

    Anyways, I tried to get the derivative using the quotient rule.

    THat is: (f * 'g) - (g * 'f)

    So:

    X^5*Sin(X)

    (x^5)(Cos(X)) = (Sin(X))(5x^4)

    But when X=.58 I got a super tiny answer.

    I believe the answer was 0.3something something.
    Thank you for any ideas/hints!
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  2. #2
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    Quote Originally Posted by EJ123 View Post
    So I am supposed to find the slope, m I presume.

    Anyways, I tried to get the derivative using the quotient rule.

    THat is: (f * 'g) - (g * 'f)

    So:

    X^5*Sin(X)

    (x^5)(Cos(X)) = (Sin(X))(5x^4)

    But when X=.58 I got a super tiny answer.

    I believe the answer was 0.3something something.
    Thank you for any ideas/hints!
    Use the product rule

    (f\cdot g)'=f\cdot g'+g\cdot f'
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