I am trying to solve for the x's for y=ax^3+bx^2+cx+d.
It cuts the y-axis at (0,30). The gradient at this point is -1.
The gradient where x=1, is -17 and the f ``(x) at this point is -10.
I s.t the coordinates given; set f `(x) =-1 and
I think d=30 and c=-1.
So I need to solve for a,b.
I didn't think solving for x would be this tricky? What have I missed?