I know its U substitution with u= 4+3s^2 and du=6xdx but I dont know how to make 13 s drop out?
Thanks to anyone who can help
Amanda
Which means $\displaystyle dx = \dfrac{du}{6x}$. Substituting $\displaystyle \dfrac{du}{6x}$ for $\displaystyle dx$ and $\displaystyle u$ for $\displaystyle 4+3s^2$ gives: $\displaystyle \int\left(\dfrac{13s}{u}\right)\left(\dfrac{du}{6s }\right)\;{du} = \int\left(\dfrac{13s}{6s}\right)\left(\dfrac{1}{u} \right)\;{du}$. The $\displaystyle s$ in the numerator and the $\displaystyle s$ in the denominator cancel, so it becomes: $\displaystyle \frac{13}{6}\int\frac{1}{u}du$.