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Math Help - Integration using U sub

  1. #1
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    Integration using U sub



    I know its U substitution with u= 4+3s^2 and du=6xdx but I dont know how to make 13 s drop out?
    Thanks to anyone who can help
    Amanda
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  2. #2
    Member Black's Avatar
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    du=6s \, ds \Longrightarrow \frac{13}{6}du=13s \, ds.
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  3. #3
    Newbie Homeomorphism's Avatar
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    Quote Originally Posted by Casas4 View Post
    I know its U substitution with u= 4+3s^2 and du=6xdx ...
    Which means dx = \dfrac{du}{6x}. Substituting \dfrac{du}{6x} for dx and u for 4+3s^2 gives: \int\left(\dfrac{13s}{u}\right)\left(\dfrac{du}{6s  }\right)\;{du} = \int\left(\dfrac{13s}{6s}\right)\left(\dfrac{1}{u}  \right)\;{du}. The s in the numerator and the s in the denominator cancel, so it becomes:  \frac{13}{6}\int\frac{1}{u}du.
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