Consider the equation and find the value of C
The summation to infinity with n=2, of (1+c)^-n = 3
Sorry I'm not sure how to put up all the symbols, but hopefully I've explained it well enough. Thanks
Here is the LaTeX code.
[tex]\sum\limits_{n = 2}^\infty {\frac{1}{{\left( {1 + c} \right)^n }}} = 3[/tex] gives $\displaystyle \sum\limits_{n = 2}^\infty {\frac{1}{{\left( {1 + c} \right)^n }}} = 3$.
Note that $\displaystyle \sum\limits_{n = 2}^\infty {\frac{1}
{{\left( {1 + c} \right)^n }}} = \frac{{\frac{1}
{{\left( {1 + c} \right)^2 }}}}
{{1 - \frac{1}
{{1 +c}}}},~c>0$