Results 1 to 4 of 4

Math Help - Max/Min Online Webwork Problem

  1. #1
    Super Member
    Joined
    Oct 2006
    Posts
    679
    Awards
    1

    Max/Min Online Webwork Problem

    Here is the question:






    Thus I went about trying to solve this problem in this manner. Note that the Minimum value is correct but the system will not accept 10 as an answer for the maximum value.

    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by qbkr21 View Post
    Here is the question:






    Thus I went about trying to solve this problem in this manner. Note that the Minimum value is correct but the system will not accept 10 as an answer for the maximum value.

    remember that absolute max is different from local max. the derivative gives you the local max. the absolute max is the highest point in the interval, IT DOES NOT HAVE TO BE A CRITICAL POINT.

    check the end points, we get:

    (15, 28585) and
    (-6, -2222)

    so the absolute max is 28585
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    Joined
    Oct 2006
    Posts
    679
    Awards
    1
    Quote Originally Posted by Jhevon View Post
    remember that absolute max is different from local max. the derivative gives you the local max. the absolute max is the highest point in the interval, IT DOES NOT HAVE TO BE A CRITICAL POINT.

    check the end points, we get:

    (15, 28585) and
    (-6, -2222)

    so the absolute max is 28585
    Bingo You were right, but what did you do to maximize each coordinate? Did you stick the intervals that x was between back into f(x)?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by qbkr21 View Post
    Bingo You were right, but what did you do to maximize each coordinate? Did you stick the intervals that x was between back into f(x)?
    yes, i found f(-6) and f(15). if one of those is lower than the y-value of all critical poitns, then it is the absolute min, if one is higher than all the y-values of the critical points, it is the absolute max.

    so always remember to check the endpoints for absolute max and mins
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: June 29th 2010, 07:38 PM
  2. Two Webwork Questions (Second order)
    Posted in the Differential Equations Forum
    Replies: 5
    Last Post: October 30th 2009, 12:32 PM
  3. A few Webwork Integral problems have me stuck.
    Posted in the Calculus Forum
    Replies: 13
    Last Post: May 30th 2007, 05:05 PM
  4. WeBWork Calculus 1241 Sec 4.6 due 4/20/2007
    Posted in the Calculus Forum
    Replies: 4
    Last Post: April 17th 2007, 08:31 PM
  5. Webwork Max and Min Values #2
    Posted in the Calculus Forum
    Replies: 11
    Last Post: April 14th 2007, 09:40 PM

Search Tags


/mathhelpforum @mathhelpforum