Results 1 to 2 of 2

Math Help - integration problem

  1. #1
    Member
    Joined
    Oct 2009
    Posts
    201

    integration problem

    Given that \frac{dp}{dt}=kt^2 where k is constant.Given also p=\frac{11}{3} and \frac{dp}{dt}=-2 when t=-2.Express  p in term of  t
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Dec 2009
    Posts
    3,120
    Thanks
    1
    Quote Originally Posted by mastermin346 View Post
    Given that \frac{dp}{dt}=kt^2 where k is constant.Given also p=\frac{11}{3} and \frac{dp}{dt}=-2 when t=-2.Express  p in term of  t
    \frac{dp}{dt}=kt^2\ \Rightarrow\ p=\frac{k}{3}t^3+C

    \frac{dp}{dt}=-2\ for\ t=-2\ \Rightarrow\ k(-2)^2=-2\ \Rightarrow\ 4k=-2

    From that you find k and substitute that value of k to find C.

    \frac{11}{3}=\left(-\frac{1}{2}\right)\left(\frac{1}{3}\right)(-2)^3+C
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Integration Problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 27th 2011, 10:09 PM
  2. Problem with Integration
    Posted in the Calculus Forum
    Replies: 6
    Last Post: May 30th 2010, 07:53 PM
  3. Replies: 2
    Last Post: February 19th 2010, 10:55 AM
  4. Integration problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: April 6th 2009, 06:47 PM
  5. integration problem
    Posted in the Calculus Forum
    Replies: 10
    Last Post: February 25th 2008, 03:06 PM

Search Tags


/mathhelpforum @mathhelpforum