Can anyone help me in calculating relative extrema for the following: f(x)=x^4 - V^45 i m stuck and need help, i would really appreciate. thanks
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That is $\displaystyle x^{4}-v^{45}$?
yes
Originally Posted by andrewsmith Can anyone help me in calculating relative extrema for the following: f(x)=x^4 - V^45 i m stuck and need help, i would really appreciate. thanks Solve f'(x) = 0. (Not really necessary since you should know what the graph of y = f(x) looks like).
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