1. ## quick derivative help

g(t)= 4sec(t) + tan(t)

when finding d/dx g(t), is the derivative of
4sec(t)
0(tan x) = 0?

or am i doing that wrong?

2. Originally Posted by ExCaLiBuR
g(t)= 4sec(t) + tan(t)

when finding d/dx g(t), is the derivative of
4sec(t)
0(tan x) = 0?

or am i doing that wrong?
I think you are getting confusing with something else. I don't see where you got the 0 from...

$\frac{d}{dx}g(t) = 4\sec(t)\tan(t) + sec^2t$

You could factorize the sec(t) if you wanted to.