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Math Help - More fun conceptual stuff :(

  1. #1
    Junior Member Selim's Avatar
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    More fun conceptual stuff :(

    Given cos(x)= \frac{1-u^2}{1+u^2} then

    u^2=

    sin(x)= u

    dx=
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  2. #2
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    Quote Originally Posted by Selim View Post
    Given cos(x)= \frac{1-u^2}{1+u^2} then

    u^2=\frac{1-cos(x)}{1+cos(x)}

    sin(x)=\frac{2u}{1+u^2}

    dx=\frac{2\,du}{1+u^2}
    u=\frac{sin(x)}{1+cos(x)}=tan({\frac{x}{2}})

    These are the substitutions that were used for \int\frac{1}{3+2cos(x)}\,dx
    Last edited by ione; March 21st 2010 at 10:59 PM.
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