Given $\displaystyle cos(x)= \frac{1-u^2}{1+u^2}$ then

$\displaystyle u^2$=

sin(x)= u

dx=

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- Mar 21st 2010, 09:57 PMSelimMore fun conceptual stuff :(
Given $\displaystyle cos(x)= \frac{1-u^2}{1+u^2}$ then

$\displaystyle u^2$=

sin(x)= u

dx= - Mar 21st 2010, 10:49 PMione