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Math Help - Tough Calculus Integral problem

  1. #1
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    Tough Calculus Integral problem

    Looking to solve sec^3(x)dx
    and I can't figure it out. Any help guys? Thank you so much,
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  2. #2
    Master Of Puppets
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    Does this help?

    \int\sec^3x~dx = \int\sec^2x \sec x~dx = \int\frac{1+\tan^2 x}{ \cos x}~dx = \int\frac{1}{ \cos x}~dx+ \int\frac{\tan^2 x}{ \cos x}~dx

    Remember \tan x = \frac{\sin x }{\cos x} and \frac{d}{dx}(\sin x) = \cos x
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