Can you show that if then
If you can then choose .
Hi everyone. I'm a bit stuck on doing this Delta Epsilon prrof for the limit
lim x->1 =1
I have (I'll use brakets for absolute values)
( -1)<e and 0<(x-1)<d
so
(x-1)<
so d= ?????
ok then i'm stuck and don't know where from here...i'm not even sure if i have done that right
any help?
Hi
If i have f(x)-L < e
then sqrt(x)-1 < e
if i then multiply by ( )
i get x-1 < e( )
is that right?
but if [x-1] = ( )( )
if i then cancel from both sides i'm back where i started at <e
I think i just keep turning back on myself....I'm not being able to get a 'd'