# Math Help - Find the partial fraction decomposition:

1. ## Find the partial fraction decomposition:

Find the partial fraction decomposition:

$\frac{3x+3}{x^2+3x}$

2. Originally Posted by Selim
Find the partial fraction decomposition:

$\frac{3x+3}{x^2+3x}$
$\frac{3x+3}{x(x+3)} = \frac{A}{x} + \frac{B}{x+3}$

$3x+3 = A(x+3) + Bx$

solve for A and B

3. Is the answer simply $\frac{A}{x} + \frac{B+C}{x+3}$

Aw, thanks, I would have been incorrect. Thank you again, Skeeter.

So then using x=0 and x=-3 I found that A=1 and B=2.

4. Originally Posted by Selim
Is the answer simply $\frac{A}{x} + \frac{Bx+C}{x+3}$ ... no

$3x+3 = A(x+3) + Bx$

let $x = 0$ ... $A = 1$

let $x = -3$ ... $B = 2$

$\frac{3x+3}{x(x+3)} = \frac{1}{x} + \frac{2}{x+3}$