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Thread: Find the partial fraction decomposition:

  1. #1
    Junior Member Selim's Avatar
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    Find the partial fraction decomposition:

    Find the partial fraction decomposition:

    $\displaystyle \frac{3x+3}{x^2+3x}$
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  2. #2
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    Quote Originally Posted by Selim View Post
    Find the partial fraction decomposition:

    $\displaystyle \frac{3x+3}{x^2+3x}$
    $\displaystyle \frac{3x+3}{x(x+3)} = \frac{A}{x} + \frac{B}{x+3}$

    $\displaystyle 3x+3 = A(x+3) + Bx$

    solve for A and B
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  3. #3
    Junior Member Selim's Avatar
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    Is the answer simply $\displaystyle \frac{A}{x} + \frac{B+C}{x+3}$

    Aw, thanks, I would have been incorrect. Thank you again, Skeeter.

    So then using x=0 and x=-3 I found that A=1 and B=2.
    Last edited by Selim; Mar 21st 2010 at 01:49 PM.
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  4. #4
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    Quote Originally Posted by Selim View Post
    Is the answer simply $\displaystyle \frac{A}{x} + \frac{Bx+C}{x+3}$ ... no

    $\displaystyle 3x+3 = A(x+3) + Bx $

    let $\displaystyle x = 0$ ... $\displaystyle A = 1$

    let $\displaystyle x = -3$ ... $\displaystyle B = 2$

    $\displaystyle \frac{3x+3}{x(x+3)} = \frac{1}{x} + \frac{2}{x+3}$
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