Problem with an integral

**Bart** · March 21st 2010, 12:05 PM

The integral is $\int{\frac{1-3*x}{3+2*x}}dx$ .

According to Maple I should first rewrite it as $\frac{-3}{2} + \frac{11}{2}\frac{1}{3 + 2*x}$ and then solve it.
My problem is that I don't know how to rewrite it, after that I can solve it (I know how to use the rules for integration) but how to get there?
I would like a method which works all the time.

**skeeter** · March 21st 2010, 12:17 PM

Originally Posted by Bart

The integral is $\int{\frac{1-3*x}{3+2*x}}dx$ .

According to Maple I should first rewrite it as $\frac{-3}{2} + \frac{11}{2}\frac{1}{3 + 2*x}$ and then solve it.
My problem is that I don't know how to rewrite it, after that I can solve it (I know how to use the rules for integration) but how to get there?
I would like a method which works all the time.

when the degree of the numerator $\ge$ the degree of the denominator, perform long division.

**Bart** · March 21st 2010, 12:55 PM

Problem solved.

If I have a question about another integral, should I then post it in the same topic or make a new topic for it?

**skeeter** · March 21st 2010, 01:01 PM

Originally Posted by Bart

Problem solved.

If I have a question about another integral, should I then post it in the same topic or make a new topic for it?

new thread

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